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5+4x-4.9x^2=0
a = -4.9; b = 4; c = +5;
Δ = b2-4ac
Δ = 42-4·(-4.9)·5
Δ = 114
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-\sqrt{114}}{2*-4.9}=\frac{-4-\sqrt{114}}{-9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+\sqrt{114}}{2*-4.9}=\frac{-4+\sqrt{114}}{-9.8} $
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